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標(biāo)題: 兩只蝴蝶蜂鳴器 [打印本頁(yè)]

作者: c1049462012 時(shí)間: 2018-4-9 21:18
標(biāo)題: 兩只蝴蝶蜂鳴器
代碼
/========================================================//
#include <reg51.h>          // 這是  單片機(jī)音樂(lè)代碼生成器  生成的代碼
#define uchar unsigned char
sbit beepIO=P1^5;                // 輸出為 P1.5  可以修改成其它 IO 口
uchar m,n;
uchar code T[49][2]={{0,0},
{0xF8,0x8B},{0xF8,0xF2},{0xF9,0x5B},{0xF9,0xB7},{0xFA,0x14},{0xFA,0x66},{0xFA,0xB9},{0xFB,0x03},{0xFB,0x4A},{0xFB,0x8F},{0xFB,0xCF},{0xFC,0x0B},
{0xFC,0x43},{0xFC,0x78},{0xFC,0xAB},{0xFC,0xDB},{0xFD,0x08},{0xFD,0x33},{0xFD,0x5B},{0xFD,0x81},{0xFD,0xA5},{0xFD,0xC7},{0xFD,0xE7},{0xFE,0x05},
{0xFE,0x21},{0xFE,0x3C},{0xFE,0x55},{0xFE,0x6D},{0xFE,0x84},{0xFE,0x99},{0xFE,0xAD},{0xFE,0xC0},{0xFE,0x02},{0xFE,0xE3},{0xFE,0xF3},{0xFF,0x02},
{0xFF,0x10},{0xFF,0x1D},{0xFF,0x2A},{0xFF,0x36},{0xFF,0x42},{0xFF,0x4C},{0xFF,0x56},{0xFF,0x60},{0xFF,0x69},{0xFF,0x71},{0xFF,0x79},{0xFF,0x81}
};
uchar code music[][2]={{0,4},
{23,4},{21,4},{23,16},{23,4},{21,4},{23,4},{21,4},{19,16},{16,4},{19,4},{21,8},{21,4},{23,4},{21,4},{19,4},{16,4},{19,4},{14,24},
{23,4},{21,4},{23,16},{23,4},{21,4},{23,4},{21,4},{19,24},{16,4},{19,4},{21,8},{21,4},{23,4},{21,4},{19,4},{16,4},{19,4},{21,24},
{23,4},{21,4},{23,16},{23,4},{21,4},{23,4},{21,4},{19,16},{16,4},{19,4},{21,8},{21,4},{23,4},{21,4},{19,4},{16,4},{19,4},{14,24},
{23,4},{26,4},{26,16},{26,4},{28,4},{26,4},{23,24},{21,4},{23,4},{21,8},{21,4},{23,4},{21,4},{19,4},{16,4},{16,2},{19,2},{19,24},{0,20},
{26,4},{26,4},{28,4},{31,4},{30,4},{30,4},{28,4},{23,4},{21,4},{21,4},{23,16},{0,4},{23,4},{23,4},{26,4},{28,8},{28,12},{16,4},{23,4},{21,4},
{21,24},{23,4},{26,4},{26,4},{23,4},{26,8},{0,4},{31,8},{30,4},{28,4},{30,4},{23,8},{0,4},{28,4},{28,4},{30,4},{28,4},{26,4},{23,4},{21,8},{23,4},{21,4},{23,4},{26,16},
{0xFF,0xFF}};
void delay(uchar p)
{
uchar i,j;
for(;p>0;p--)
for(i=181;i>0;i--)
for(j=181;j>0;j--);
}
void pause()
{
uchar i,j;
for(i=150;i>0;i--)
for(j=150;j>0;j--);
}
void T0_int() interrupt 1
{
beepIO=!beepIO;
TH0=T[m][0]; TL0=T[m][1];
}
void main()
{
uchar i=0;
TMOD=0x01;  EA=1; ET0=1;
while(1)
   {
      m=music[i][0];n=music[i][1];
         if(m==0x00)
         {TR0=0;delay(n);i++;}
         else if(m==0xFF)
         {TR0=0;delay(30);i=0;}
         else if(m==music[i+1][0])
         {TR0=1;delay(n);TR0=0;pause();i++;}
         else
         {TR0=1;delay(n);i++;}
   }
}

兩只蝴蝶歌.zip

24.46 KB, 下載次數(shù): 7, 下載積分: 黑幣 -5

作者: 宮商角徵羽smile 時(shí)間: 2018-4-17 17:51
程序運(yùn)行沒(méi)問(wèn)題，有proteus仿真圖嗎？

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