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標(biāo)題: 中穎單片機(jī)79H1612A采集不到數(shù)據(jù)是怎么回事？ [打印本頁]

作者: qiangrenliwei 時間: 2019-7-20 16:46
標(biāo)題: 中穎單片機(jī)79H1612A采集不到數(shù)據(jù)是怎么回事？
本帖最后由 qiangrenliwei 于 2019-7-20 18:48 編輯

請教各位朋友，
中穎單片機(jī)79H1612A單片機(jī)AD采集不到數(shù)據(jù)是怎么回事？
下面是我的程序：

#include <SH79F1612A.H>
#include <intrins.h>
#include <config.h>

typedef unsigned char    uint8;
typedef signed char    int8;
typedef unsigned short    uint16;
typedef signed short    int16;
typedef unsigned long    uint32;
typedef signed long    int32;

uint16 adval;

void delay(uint16 i)
{
      while(i--);
}

void Init_IO()
{
            P4M0 = 0x00;
            P4M1 = 0x04;
            P3M0 = 0x00;
            P3M1 = 0x04;
}

uint16 Sample_AD(uint8 ch,uint8 smdt)
{
      uint16 adval;

if(smdt==0)
{
   ADT=Bin(00000000);
}
else
{
   ADT  =Bin(11101111);
}

switch(ch)
{
   case 0:    //AN0
            ADCH=Bin(00000001);
      ADCON=Bin(10000001);
            break;
   case 1:    //AN1
            ADCH=Bin(00000010);
      ADCON=Bin(10000011);
            break;
   case 2:    //AN2
            ADCH=Bin(00000100);
      ADCON=Bin(10000101);
            break;
   case 3:    //AN3
            ADCH=Bin(00001000);
      ADCON=Bin(10000111);
            break;
   case 4:    //AN4
            ADCH=Bin(00010000);
      ADCON=Bin(10001001);
            break;
   case 5:    //AN5
            ADCH=Bin(00100000);
      ADCON=Bin(10001011);
            break;
   case 6:    //AN6
            ADCH=Bin(01000000);
      ADCON=Bin(10001101);
            break;
   case 7:    //AN7
            ADCH=Bin(10000000);
      ADCON=Bin(10001111);
            break;
   default:
            break;
}

while((ADCON&Bin(01000000))==0)
{
   _nop_();
}

adval=ADDH*4+ADDL;
ADCON=Bin(00000000);

return(adval);
}
/*********************************************************************************************

** oˉêyÃû3Æ: main
** oˉêyÃèêö: Ö÷oˉêy
** êäèë2Îêy: ÎT
** êä3ö2Îêy: ÎT
*********************************************************************************************/
void main()
{
            P4_2 = 1;
            Init_IO();
            //Init_AD();
while(1)
{
Sample_AD(1,1);
            //GetADCH_8();
            //GetADCL_8();
            //GetADC_16();
            if(adval >1001001110)
            {
                     P4_2 = 0;
                     P3_2 = 0;
                     delay(50000);
               P3_2 = 1;
               delay(50000);

      }
      else
      {
               P4_2 = 1;
      }
}
}

作者: qiangrenliwei 時間: 2019-7-20 18:46
問題補(bǔ)充：adval=ADDH*4+ADDL，這句看不明白為什么ADDH*4，這款單片機(jī)是10位的AD

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