51單片機(jī)編程怎么用獨(dú)立按鍵控制兩首歌的播放，求解決~急~~~~

ID:270099 · 發(fā)表于 2018-1-2 11:50

想通過按鍵K1，K2控制播放兩首歌，不知道為什么只能播第一首，小白一只，請多指教

#include <REG52.H>

#include <INTRINS.H>

sbit Beep = P1^5;

volatile bit Flag=0;

sbit k1=P3^1;

sbit k2=P3^0;

unsigned char n=0; //n為節(jié)拍常數(shù)變量、

unsigned char code music_tab1[] ={

0x18, 0x30, 0x1C , 0x10, //格式為: 頻率常數(shù), 節(jié)拍常數(shù), 頻率常數(shù), 節(jié)拍常數(shù),

0x20, 0x40, 0x1C , 0x10,

0x18, 0x10, 0x20 , 0x10,

0x1C, 0x10, 0x18 , 0x40,

0x1C, 0x20, 0x20 , 0x20,

0x1C, 0x20, 0x18 , 0x20,

0x20, 0x80, 0xFF , 0x20,

0x30, 0x1C, 0x10 , 0x18,

0x20, 0x15, 0x20 , 0x1C,

0x20, 0x20, 0x20 , 0x26,

0x40, 0x20, 0x20 , 0x2B,

0x20, 0x26, 0x20 , 0x20,

0x20, 0x30, 0x80 , 0xFF,

0x20, 0x20, 0x1C , 0x10,

0x18, 0x10, 0x20 , 0x20,

0x26, 0x20, 0x2B , 0x20,

0x30, 0x20, 0x2B , 0x40,

0x20, 0x20, 0x1C , 0x10,

0x18, 0x10, 0x20 , 0x20,

0x26, 0x20, 0x2B , 0x20,

0x30, 0x20, 0x2B , 0x40,

0x20, 0x30, 0x1C , 0x10,

0x18, 0x20, 0x15 , 0x20,

0x1C, 0x20, 0x20 , 0x20,

0x26, 0x40, 0x20 , 0x20,

0x2B, 0x20, 0x26 , 0x20,

0x20, 0x20, 0x30 , 0x80,

0x20, 0x30, 0x1C , 0x10,

0x20, 0x10, 0x1C , 0x10,

0x20, 0x20, 0x26 , 0x20,

0x2B, 0x20, 0x30 , 0x20,

0x2B, 0x40, 0x20 , 0x15,

0x1F, 0x05, 0x20 , 0x10,

0x1C, 0x10, 0x20 , 0x20,

0x26, 0x20, 0x2B , 0x20,

0x30, 0x20, 0x2B , 0x40,

0x20, 0x30, 0x1C , 0x10,

0x18, 0x20, 0x15 , 0x20,

0x1C, 0x20, 0x20 , 0x20,

0x26, 0x40, 0x20 , 0x20,

0x2B, 0x20, 0x26 , 0x20,

0x20, 0x20, 0x30 , 0x30,

0x20, 0x30, 0x1C , 0x10,

0x18, 0x40, 0x1C , 0x20,

0x20, 0x20, 0x26 , 0x40,

0x13, 0x60, 0x18 , 0x20,

0x15, 0x40, 0x13 , 0x40,

0x18, 0x80, 0x00

};

unsigned char code music_tab2[] ={

0x1c,0x30,0x19,0x30,//格式為: 頻率常數(shù), 節(jié)拍常數(shù), 頻率常數(shù), 節(jié)拍常數(shù),

0x18,0x40,0x19,0x30,

0x18,0x30,0x13,0x30,

0x19,0x80,0x26,0x30,

0x26,0x30,0x1c,0x40,

0x20,0x30,0x1c,0x30,

0x18,0x30,0x20,0x60,

0x26,0x30,0x26,0x30,

0x24,0x40,0x26,0x30,

0x24,0x30,0x18,0x40,

0x26,0x60,0x18,0x20,

0x18,0x20,0x18,0x20,

0x19,0x40,0x24,0x30,

0x24,0x30,0x19,0x30,

0x19,0x60,0x1c,0x30,

0x19,0x30,0x18,0x40,

0x19,0x30,0x18,0x30,

0x13,0x30,0x19,0x60,

0x26,0x30,0x26,0x30,

0x1c,0x40,0x20,0x30,

0x1c,0x30,0x18,0x30,

0x20,0x80,0x26,0x30,

0x24,0x30,0x24,0x30,

0x18,0x30,0x19,0x20,

0x19,0x30,0x18,0x30,

0x15,0x20,0x15,0x20,

0x13,0x20,0x18,0x40,

0x18,0x30,0x19,0x30,

0x1c,0x20,0x1c,0x20,

0x19,0x30,0x20,0x30,

0x1c,0x60,0x18,0x30,

0x15,0x30,0x13,0x40,

0x15,0x30,0x13,0x30,

0x10,0x30,0x15,0x60,

0x20,0x30,0x20,0x30,

0x18,0x30,0x19,0x30,

0x18,0x30,0x13,0x30,

0x13,0x60,0x1c,0x20,

0x19,0x20,0x18,0x30,

0x19,0x30,0x15,0x20,

0x15,0x20,0x18,0x40,

0x20,0x30,0x20,0x30,

0x12,0x30,0x13,0x30,

0x15,0x30,0x18,0x30,

0x13,0xc0,0x13,0x80,

0x13,0x30,0x0e,0x80,

0x10,0x30,0x10,0x30,

0x13,0x20,0x15,0x20,

0x18,0x40,0x18,0x30,

0x15,0x30,0x18,0x20,

0x15,0x20,0x15,0x30,

0x10,0x30,0x13,0x60,

0x13,0x30,0x0e,0x60,

0x10,0x60,0x13,0x20,

0x15,0x20,0x18,0x40,

0x18,0x30,0x15,0x30,

0x15,0x20,0x18,0x20,

0x15,0x30,0x19,0x30,

0x1c,0x60,0x1c,0x30,

0x19,0x30, 0x1c,0xc0,

0x00,

};

void int0() interrupt 1 //采用中斷0 控制節(jié)拍

{ TH0=0xd8;

TL0=0xef;

n--;

}

void delay (unsigned char m) //控制頻率延時

{

unsigned i=3*m;

while(--i);

}

void delayms(unsigned char a) //豪秒延時子程序

{

while(--a); //采用while(--a) 不要采用while(a--); 各位可編譯一下看看匯編結(jié)果就知道了!

}

void main()

{ unsigned char p,m; //m為頻率常數(shù)變量

unsigned char i=0;

TMOD&=0x0f;

TMOD|=0x01;

TH0=0xd8;TL0=0xef;

IE=0x82;

if(k1==0&&Flag==0)

Flag=1;

while(k1==0&&Flag==1)

{

play:

while(Flag)

{

a: p=music_tab1;

if(p==0x00)

{ i=0, delayms(1000); goto play;} //如果碰到結(jié)束符,延時1秒,回到開始再來一遍

else if(p==0xff)

{ i=i+1;delayms(100),TR0=0; goto a;} //若碰到休止符,延時100ms,繼續(xù)取下一音符

else

{m=music_tab1[i++], n=music_tab1[i++];} //取頻率常數(shù) 和節(jié)拍常數(shù)

TR0=1; //開定時器0

while(n!=0) Beep=~Beep,delay(m); //等待節(jié)拍完成, 通過P1口輸出音頻(可多聲道哦!)

TR0=0; //關(guān)定時器0

if(k1==0&&Flag==1)

{

Flag=0;

break;

}

if(k2==0&&Flag==0)
Flag=1;
while(k2==0&&Flag==1)
{
play2:
while(Flag)
{
b: p=music_tab2;
   if(p==0x00)
{ i=0, delayms(1000); goto play2;}    //如果碰到結(jié)束符,延時1秒,回到開始再來一遍
   else if(p==0xff)
{ i=i+1;delayms(100),TR0=0; goto b;}  //若碰到休止符,延時100ms,繼續(xù)取下一音符
   else
{m=music_tab2[i++], n=music_tab2[i++];}  //取頻率常數(shù) 和節(jié)拍常數(shù)
   TR0=1;                                           //開定時器0
   while(n!=0) Beep=~Beep,delay(m);                      //等待節(jié)拍完成, 通過P1口輸出音頻(可多聲道哦!)
   TR0=0;                                           //關(guān)定時器0
if(k2==0&&Flag==1)
{
Flag=0;
break;
}
}
}

}
}

ID:164602 · 發(fā)表于 2018-1-2 13:53

你的程序，按k2都沒有反應(yīng)。
太亂了，各種花括號，你可能都不知道應(yīng)該誰和誰配對。
我修改了一下，按k2有反應(yīng)了。
但只能按一次，按k2，只能唱第二首，不停。
原因是你的那個break。
break只能跳一級循環(huán)，不能跳到最外去，所以，按了一個鍵后，就在循環(huán)里出不去了。
以下是兩個按鍵都有反應(yīng)的程序，但只能唱一首。(你的歌，第一首八月桂花、第二首叫不出名字)
#include <REG52.H>
#include <INTRINS.H>

sbit Beep =  P1^5;
volatile bit Flag=0;
sbit k1=P3^1;
sbit k2=P3^0;

unsigned char n=0;  //n為節(jié)拍常數(shù)變量、
unsigned char code music_tab1[] ={
0x18, 0x30, 0x1C , 0x10, //格式為: 頻率常數(shù), 節(jié)拍常數(shù), 頻率常數(shù), 節(jié)拍常數(shù),
0x20, 0x40, 0x1C , 0x10,
0x18, 0x10, 0x20 , 0x10,
0x1C, 0x10, 0x18 , 0x40,
0x1C, 0x20, 0x20 , 0x20,
0x1C, 0x20, 0x18 , 0x20,
0x20, 0x80, 0xFF , 0x20,
0x30, 0x1C, 0x10 , 0x18,
0x20, 0x15, 0x20 , 0x1C,
0x20, 0x20, 0x20 , 0x26,
0x40, 0x20, 0x20 , 0x2B,
0x20, 0x26, 0x20 , 0x20,
0x20, 0x30, 0x80 , 0xFF,
0x20, 0x20, 0x1C , 0x10,
0x18, 0x10, 0x20 , 0x20,
0x26, 0x20, 0x2B , 0x20,
0x30, 0x20, 0x2B , 0x40,
0x20, 0x20, 0x1C , 0x10,
0x18, 0x10, 0x20 , 0x20,
0x26, 0x20, 0x2B , 0x20,
0x30, 0x20, 0x2B , 0x40,
0x20, 0x30, 0x1C , 0x10,
0x18, 0x20, 0x15 , 0x20,
0x1C, 0x20, 0x20 , 0x20,
0x26, 0x40, 0x20 , 0x20,
0x2B, 0x20, 0x26 , 0x20,
0x20, 0x20, 0x30 , 0x80,
0x20, 0x30, 0x1C , 0x10,
0x20, 0x10, 0x1C , 0x10,
0x20, 0x20, 0x26 , 0x20,
0x2B, 0x20, 0x30 , 0x20,
0x2B, 0x40, 0x20 , 0x15,
0x1F, 0x05, 0x20 , 0x10,
0x1C, 0x10, 0x20 , 0x20,
0x26, 0x20, 0x2B , 0x20,
0x30, 0x20, 0x2B , 0x40,
0x20, 0x30, 0x1C , 0x10,
0x18, 0x20, 0x15 , 0x20,
0x1C, 0x20, 0x20 , 0x20,
0x26, 0x40, 0x20 , 0x20,
0x2B, 0x20, 0x26 , 0x20,
0x20, 0x20, 0x30 , 0x30,
0x20, 0x30, 0x1C , 0x10,
0x18, 0x40, 0x1C , 0x20,
0x20, 0x20, 0x26 , 0x40,
0x13, 0x60, 0x18 , 0x20,
0x15, 0x40, 0x13 , 0x40,
0x18, 0x80, 0x00
};
unsigned char code music_tab2[] ={
0x1c,0x30,0x19,0x30,//格式為: 頻率常數(shù), 節(jié)拍常數(shù), 頻率常數(shù), 節(jié)拍常數(shù),
0x18,0x40,0x19,0x30,
0x18,0x30,0x13,0x30,
0x19,0x80,0x26,0x30,
0x26,0x30,0x1c,0x40,
0x20,0x30,0x1c,0x30,
0x18,0x30,0x20,0x60,
0x26,0x30,0x26,0x30,
0x24,0x40,0x26,0x30,
0x24,0x30,0x18,0x40,
0x26,0x60,0x18,0x20,
0x18,0x20,0x18,0x20,
0x19,0x40,0x24,0x30,
0x24,0x30,0x19,0x30,
0x19,0x60,0x1c,0x30,
0x19,0x30,0x18,0x40,
0x19,0x30,0x18,0x30,
0x13,0x30,0x19,0x60,
0x26,0x30,0x26,0x30,
0x1c,0x40,0x20,0x30,
0x1c,0x30,0x18,0x30,
0x20,0x80,0x26,0x30,
0x24,0x30,0x24,0x30,
0x18,0x30,0x19,0x20,
0x19,0x30,0x18,0x30,
0x15,0x20,0x15,0x20,
0x13,0x20,0x18,0x40,
0x18,0x30,0x19,0x30,
0x1c,0x20,0x1c,0x20,
0x19,0x30,0x20,0x30,
0x1c,0x60,0x18,0x30,
0x15,0x30,0x13,0x40,
0x15,0x30,0x13,0x30,
0x10,0x30,0x15,0x60,
0x20,0x30,0x20,0x30,
0x18,0x30,0x19,0x30,
0x18,0x30,0x13,0x30,
0x13,0x60,0x1c,0x20,
0x19,0x20,0x18,0x30,
0x19,0x30,0x15,0x20,
0x15,0x20,0x18,0x40,
0x20,0x30,0x20,0x30,
0x12,0x30,0x13,0x30,
0x15,0x30,0x18,0x30,
0x13,0xc0,0x13,0x80,
0x13,0x30,0x0e,0x80,
0x10,0x30,0x10,0x30,
0x13,0x20,0x15,0x20,
0x18,0x40,0x18,0x30,
0x15,0x30,0x18,0x20,
0x15,0x20,0x15,0x30,
0x10,0x30,0x13,0x60,
0x13,0x30,0x0e,0x60,
0x10,0x60,0x13,0x20,
0x15,0x20,0x18,0x40,
0x18,0x30,0x15,0x30,
0x15,0x20,0x18,0x20,
0x15,0x30,0x19,0x30,
0x1c,0x60,0x1c,0x30,
0x19,0x30, 0x1c,0xc0,
0x00,
};
void int0()  interrupt 1 //采用中斷0 控制節(jié)拍
{  TH0=0xd8;
TL0=0xef;
n--;
}

void delay (unsigned char m) //控制頻率延時
{
unsigned i=3*m;
while(--i);
}

void delayms(unsigned char a)  //豪秒延時子程序
{
  while(--a);                //采用while(--a) 不要采用while(a--); 各位可編譯一下看看匯編結(jié)果就知道了!
}

void main()
{ unsigned char p,m; //m為頻率常數(shù)變量
  unsigned char i=0;
  TMOD&=0x0f;
  TMOD|=0x01;
  TH0=0xd8;TL0=0xef;
  IE=0x82;

  if(k1==0&&Flag==0)
Flag=1;
while(k1==0&&Flag==1)
{
play:
while(Flag)
{
a: p=music_tab1;
   if(p==0x00)
{ i=0, delayms(1000); goto play;}    //如果碰到結(jié)束符,延時1秒,回到開始再來一遍
   else if(p==0xff)
{ i=i+1;delayms(100),TR0=0; goto a;}  //若碰到休止符,延時100ms,繼續(xù)取下一音符
   else
{m=music_tab1[i++], n=music_tab1[i++];}  //取頻率常數(shù) 和節(jié)拍常數(shù)
   TR0=1;                                           //開定時器0
   while(n!=0) Beep=~Beep,delay(m);                      //等待節(jié)拍完成, 通過P1口輸出音頻(可多聲道哦!)
   TR0=0;                                           //關(guān)定時器0
if(k1==0&&Flag==1)
{
Flag=0;
break;
}
}
}
if(k2==0&&Flag==0)
Flag=1;
while(k2==0&&Flag==1)
{
play2:
while(Flag)
{
b: p=music_tab2;
   if(p==0x00)
{ i=0, delayms(1000); goto play2;}    //如果碰到結(jié)束符,延時1秒,回到開始再來一遍
   else if(p==0xff)
{ i=i+1;delayms(100),TR0=0; goto b;}  //若碰到休止符,延時100ms,繼續(xù)取下一音符
   else
{m=music_tab2[i++], n=music_tab2[i++];}  //取頻率常數(shù) 和節(jié)拍常數(shù)
   TR0=1;                                           //開定時器0
   while(n!=0) Beep=~Beep,delay(m);                      //等待節(jié)拍完成, 通過P1口輸出音頻(可多聲道哦!)
   TR0=0;                                           //關(guān)定時器0
if(k2==0&&Flag==1)
{
Flag=0;
break;
}
}
}

}

ID:164602 · 發(fā)表于 2018-1-2 14:28

用外部中斷吧，就是你板子上的k3、k4，用中斷，按鍵隨時都可以打斷循環(huán)程序，設(shè)置為新的播放。
我的程序，用一個k4，隨時中斷本首歌，放下一首，無論多少歌都可以的。

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51單片機(jī)編程怎么用獨(dú)立按鍵控制兩首歌的播放，求解決~急~~~~

51單片機(jī)編程怎么用獨(dú)立按鍵控制兩首歌的播放，求解決~急~~~~