請問怎么把LCD1602中的字符串換行呀

ID:278523 · 發表于 2018-4-1 22:07

請問怎么把temper換行到第二行去啊，急急急
#include <reg52.H>
#include <intrins.H>
#include <math.H>

#define uchar unsigned char
#define uint unsigned int

sbit dula = P2^6;
sbit wela = P2^7;
sbit rw = P3^6;
sbit RS = P3^5;

sbit LCDEN = P3^4;

void delayUs()
{
_nop_();
}

void delayMs(uint a)
{
uint i, j;
for(i = a; i > 0; i--)
      for(j = 100; j > 0; j--);
}

void writeComm(uchar comm)
{
   RS = 0;
P0 = comm;
LCDEN = 1;
   delayUs();
LCDEN = 0;
delayMs(1);
}

//寫數據:RS=1, RW=0;
void writeData(uchar dat)
{
   RS = 1;
   P0 = dat;
   LCDEN = 1;
delayUs();
LCDEN = 0;
delayMs(1);
}

void init()
{
rw = 0;
dula = wela = 0;
writeComm(0x38);
writeComm(0x0c);
writeComm(0x06);
writeComm(0x01);
}

void writeString(uchar * str, uchar length)
{
   uchar i;
for(i = 0; i < length; i++)
{
      writeData(str[i]);
   }
}
/**//*****************************ultrasound*******************************/

/**//*****************************DS18B20*******************************/
sbit ds = P2^2;
void dsInit()
{

unsigned int i;
ds = 0;
i = 100;
   while(i>0) i--;
ds = 1;
i = 4;
   while(i>0) i--;
}

void dsWait()
{
   unsigned int i;
   while(ds);
   while(~ds);
   i = 4;
   while(i > 0) i--;
}

bit readBit()
{
unsigned int i;
bit b;
ds = 0;
i++;
ds = 1;
i++; i++;
b = ds;
i = 8;
while(i>0) i--;
return b;
}

unsigned char readByte()
{
unsigned int i;
unsigned char j, dat;
dat = 0;
for(i=0; i<8; i++)
{
      j = readBit();

      dat = (j << 7) | (dat >> 1);
}
return dat;
}

void writeByte(unsigned char dat)
{
unsigned int i;
unsigned char j;
bit b;
for(j = 0; j < 8; j++)
{
      b = dat & 0x01;
      dat >>= 1;

      if(b)
      {
         ds = 0;       i++; i++;
         ds = 1;
         i = 8; while(i>0) i--;
      }
      else
      {
         ds = 0;
      i = 8; while(i>0) i--;
         ds = 1;
         i++; i++;
      }
}
}

void sendChangeCmd()
{
dsInit();
dsWait();
delayMs(1);
writeByte(0xcc);
writeByte(0x44);
}

void sendReadCmd()
{
dsInit();
dsWait();
delayMs(1);
writeByte(0xcc);
writeByte(0xbe);
}

int getTmpValue()
{
unsigned int tmpvalue;
int value;
float t;
unsigned char low, high;
sendReadCmd();

low = readByte();
high = readByte();

tmpvalue = high;
tmpvalue <<= 8;
tmpvalue |= low;
value = tmpvalue;

  \
t = value * 0.0625;
\
value = t * 100 + (value > 0 ? 0.5 : -0.5); //大于0加0.5, 小于0減0.5
return value;
}

void display(int v)
{
unsigned char count;
unsigned char datas[] = {0, 0, 0, 0, 0};
unsigned int tmp = abs(v);
datas[0] = tmp / 10000;
datas[1] = tmp % 10000 / 1000;
datas[2] = tmp % 1000 / 100;
datas[3] = tmp % 100 / 10;
datas[4] = tmp % 10;
writeComm(0xc0+7);
if(v < 0)
{
      writeString("- ", 2);
}
else
{
   writeString("+ ", 2);
}
if(datas[0] != 0)
{
      writeData('0'+datas[0]);
}
for(count = 1; count != 5; count++)
{
      writeData('0'+datas[count]);
      if(count == 2)
      {
         writeData('.');
      }
}
writeData(0xdf);
writeData(0x43);
}
/**//*****************************DS18B20*******************************/

void main()
{
uchar table[] = "temper:";
sendChangeCmd();
init();
writeComm(0xc0);
writeString(table, 7);
while(1)
{
      delayMs(1000); //溫度轉換時間需要750ms以上
      writeComm(0xc0);
      display(getTmpValue());
      sendChangeCmd();
}
}

ID:137239 · 發表于 2018-4-2 09:52

uchar code addr[]={0x00,0x01,0x02,0x03,0x04,0x05,0x06,0x07,0x08,0x09,0x0a,0x0b,0x0c,0x0d,0x0e,0x0f,//第一行顯示位置
               0x40,0x41,0x42,0x43,0x44,0x45,0x46,0x47,0x48,0x49,0x4a,0x4b,0x4c,0x4d,0x4e,0x4f//第二行顯示位置
   };

void zuobiao(uchar x,uchar y,uchar *s)
{
uchar dizhi;
dizhi=addr[16*x+y];
Cmd(dizhi | 0x80);
while(*s>0)
   {
      Data(*s);
   s++;
   }
}

zuobiao(1,0,table)；

ID:137239 · 發表于 2018-4-2 10:14

writeComm(0x80+0x40);
writeString(table, 7);
也可以，你試試

ID:286600 · 發表于 2018-4-4 21:30

指定顯示位置呀

ID:302510 · 發表于 2018-4-5 20:10

我感覺也是
writeComm(0x80+0x40);
writeString(table, 7);

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請問怎么把LCD1602中的字符串換行呀