單片機為核心的8位競賽搶答器仿真和源程序倒計時剩余時間還未完成

ID:362588 · 發表于 2018-7-1 16:49

1）搶答器同時供8名選手或8個代表隊比賽，分別用8個按鈕s1-s8表示；

2）設置一個系統清除和搶答控制開關Key1和Key2。

3）搶答器具有鎖存與顯示功能。即選手按下按鈕，鎖存相應編號，顯示該選手編號至數碼管，并且該編號保存至主持人按下清除鍵Key1清除為止。

4）搶答器具有定時搶答功能，一次搶答設定的時間為30秒。主持人按下搶答控制開關Key2，搶答才能開始，啟動定時器，并將倒數計時時間用數碼管顯示。若定時時間到，無人搶答，則該輪搶答結束，系統通過蜂鳴器報警，選手禁止搶答。

5）選手在設定的時間內進行搶答，搶答有效，定時器停止工作，蜂鳴器報警，數碼管顯示選手編號及倒計時剩余時間，并保持到主持人將系統清除為止。

仿真原理圖如下（proteus仿真工程文件可到本帖附件中下載）

單片機源程序如下:

#include <reg52.h>
//共陰極數碼管編碼表 0 - f顯示
unsigned char code table[]={0x3f,0x06,0x5b,0x4f,0x66,
0x6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,
0x39,0x5e,0x79,0x71};
//變量定義
sbit start_stop = P3^6;
sbit reset = P3^7;
sbit LE =P3^0;
sbit key1 = P1^0;
sbit key2 = P1^1;
sbit key3 = P1^2;
sbit key4 = P1^3;
sbit key5 = P1^4;
sbit key6 = P1^5;
sbit key7 = P1^6;
sbit key8 = P1^7;
sbit state = P3^4;
sbit start=P3^1;
bit start_stop_flag = 0;
bit key1_flag = 0;
bit key2_flag = 0;
bit key3_flag = 0;
bit key4_flag = 0;
bit key5_flag = 0;
bit key6_flag = 0;
bit key7_flag = 0;
bit key8_flag = 0;
bit reset_flag = 0;
bit action = 0;
bit start_flag=0;
unsigned char second = 15;
unsigned char timer0_count = 0;
unsigned char number = 0;
unsigned char number_display = 0;
//延時函數
void delay(unsigned int z)
{
unsigned int x,y;
for(x=z;x>0;x--)
for(y=110;y>0;y--);
}
void Play(unsigned char t)
{
unsigned char i;
for(i=0;i<100;i++)
{
state=~state;
delay(t);
}
state=0;
}
//數碼管顯示驅動函數
void display(unsigned char number,unsigned char second)
{
unsigned char second_first,second_second;
second_first = second / 10;
second_second = second % 10;
P2 = 0xfe;
P0 = table[number];
delay(1);
P2 = 0xfb;
P0 = table[second_first];
delay(1);
P2 = 0xf7;
P0 = table[second_second];
delay(1);
}
//開始鍵掃描函數
void start_stop_keyscan()
{
if(start_stop == 0)
{
delay(8);
if((start_stop == 0)&&(!start_stop_flag))
{
start_stop_flag = 1;
action = 1;
TR0 = 1;
//state =0;
Play(1);
}
}
else
{
start_stop_flag = 0;
}
}
//八位搶答鍵掃描函數
unsigned char key_scan8()
{
if(key1 == 0)
{
delay(8);
if((key1 == 0)&&(!key1_flag))
{
key1_flag = 1;
number = 1;
number_display = number;
Play(2);
LE=0;
}
}
else
{
key1_flag = 0;
number = 0;
}
if(key2 == 0)
{
delay(8);
if((key2 == 0)&&(!key2_flag))
{
key2_flag = 1;
number = 2;
number_display = number;
Play(2);
LE=0;
}
}
else
{
key2_flag = 0;
number = 0;
}
if(key3 == 0)
{
delay(8);
if((key3 == 0)&&(!key3_flag))
{
key3_flag = 1;
number = 3;
number_display = number;
Play(2);
LE=0;
}
}
else
{
key3_flag = 0;
number = 0;
}
if(key4 == 0)
{
delay(8);
if((key4 == 0)&&(!key4_flag))
{
key4_flag = 1;
number = 4;
number_display = number;
Play(2);
LE=0;
}
}
else
{
key4_flag = 0;
number = 0;
}
if(key5 == 0)
{
delay(8);
if((key5 == 0)&&(!key5_flag))
{
key5_flag = 1;
number = 5;
number_display = number;
Play(2);
LE=0;
}
}
else
{
key5_flag = 0;
number = 0;
}
if(key6 == 0)
{
delay(8);
if((key6 == 0)&&(!key6_flag))
{
key6_flag = 1;
number = 6;
number_display = number;
Play(2);
LE=0;
}
}
else
{
key6_flag = 0;
number = 0;
}
if(key7 == 0)
{
delay(8);
if((key7 == 0)&&(!key7_flag))
{
key7_flag = 1;
number = 7;
number_display = number;
Play(2);
LE=0;
}
}
else
{
key7_flag = 0;
number = 0;
}
if(key8 == 0)
{
delay(8);
if((key8 == 0)&&(!key8_flag))
{
key8_flag = 1;
number = 8;
number_display = number;
Play(2);
LE=0;
}
}
else
{
key8_flag = 0;
number = 0;
}
if(number_display != 0)
{
return 1;
}
else
{
return 0;
}
}
//復位鍵掃描函數
void reset_keyscan()
{
if(reset == 0)
{
delay(8);
if((reset == 0)&&(!reset_flag))
{ second=15;
reset_flag = 1;
number_display = 0;
LE = 1;
//state = 1;
}
}
else
{
reset_flag = 0;
}
}
//主函數
void main()
{
TMOD=0x01;
TH0=0x3C;
TL0=0xB0;
EA=1;
ET0=1;
TR0=0;
while(1)
{ while((start == 0)&&(!start_flag))
{ start_stop_keyscan();
reset_keyscan();
while(action)
{
while(!key_scan8())
{
display(number_display,second);
if(second == 0)
{
……………………
…………限于本文篇幅余下代碼請從51黑下載附件…………

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ID:365098 · 發表于 2018-7-5 09:24

兄弟倒計時剩余時間顯示不出來啊？

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單片機為核心的8位競賽搶答器仿真和源程序 倒計時剩余時間還未完成

單片機為核心的8位競賽搶答器仿真和源程序倒計時剩余時間還未完成