單片機秒表程序,怎么在不改動的情況下加個按鍵控制秒表的暫停和計時？

ID:462433 · 發表于 2019-1-11 21:38

這是個秒表怎么在不改動的情況下加個按鍵控制秒表的暫停和計時？

#include<reg51.h>
#define uchar unsigned char
#define ab P0
uchar int_time;
uchar a,b;
sbit LSA = P2^2;
sbit LSB = P2^3;
sbit LSC = P2^4;
unsigned char code table[] = {0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x79,0x71};
uchar displaydata[8];
void digdisplay();
void clock(a,b)
{
displaydata[0] = table[b/10];
displaydata[1] = table[b%10];
displaydata[2] = 0x40;
displaydata[3] = table[a/10];
displaydata[4] = table[a%10];
digdisplay();
}
/***********************************
* Ö÷oˉêy
***********************************/
void main()
{
TMOD = 0X01;
TH0 = (65536-46083)/256;
TL0 = (65536-46083)/256;
EA = 1;
ET0 = 1;
TR0 = 1;
int_time = 0;
a =0;b = 0;
while(1)
{
clock(a,b);
}
}
void digdisplay()
{
uchar i,j;
for(i=0;i<5;i++)
{
switch(i)
{
case 0:
LSA = 0;LSB = 0;LSC = 0;break;
case 1:
LSA = 1;LSB = 0;LSC = 0;break;
case 2:
LSA = 0;LSB = 1;LSC = 0;break;
case 3:
LSA = 1;LSB = 1;LSC = 0;break;
case 4:
LSA = 0;LSB = 0;LSC = 1;break;
}
ab = displaydata[i];
j = 50;
while(j--);
ab = 0x00;
}
}
void TO_time() interrupt 1
{
TH0 = (65536-50000)/256;
TL0 = (65536-50000)%256;
int_time++;
if(int_time == 2)
{
int_time = 0;
a++;
}
if(a == 10)
{
b++;
a=0;
}
if(b == 60)
{
b = 0;
}
}

復制代碼

ID:183978 · 發表于 2019-1-12 02:34

可以考慮掉電模式

ID:213173 · 發表于 2019-1-12 10:55

不改動怎么加按鍵功能？給你改成單鍵60分鐘百分秒表。1ms數碼管動態顯示。
#include<reg51.h>
#define uchar unsigned char
#define uint unsigned int
#define ab P0
//uchar int_time;
uchar b,c;
uint a;
sbit LSA = P2^2;
sbit LSB = P2^3;
sbit LSC = P2^4;
sbit key1 = P3^0;

unsigned char code table[] = {0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x79,0x71};
uchar displaydata[8];
bit d;
void digdisplay();
void keyscan();

void clock(a,b)
{
      displaydata[0] = table[c/10];
      displaydata[1] = table[c%10];
      displaydata[3] = table[b/10];
      displaydata[4] = table[b%10];
      displaydata[6] = table[a/100%10];
      displaydata[7] = table[a/10%10];

}
/***********************************
* ?÷oˉêy
***********************************/
void main()
{
TMOD= 0x01; //設置定時器模式
TL0 = 0x66; //設置定時初值1ms
TH0 = 0xFC; //設置定時初值
EA = 1;
ET0 = 1;
TR0 = 1;
displaydata[2] = 0x40;
displaydata[5] = 0x40;
a =0;b = 0;
while(1)
{
keyscan();
clock(a,b);
}
}

void digdisplay()
{
static uchar i=0;
ab = 0x00;
switch(i)
{
   case 0:
   LSA = 0;LSB = 0;LSC = 0;ab = displaydata[i];i++;break;
   case 1:
   LSA = 1;LSB = 0;LSC = 0;ab = displaydata[i];i++;break;
   case 2:
   LSA = 0;LSB = 1;LSC = 0;ab = displaydata[i];i++;break;
   case 3:
   LSA = 1;LSB = 1;LSC = 0;ab = displaydata[i];i++;break;
   case 4:
   LSA = 0;LSB = 0;LSC = 1;ab = displaydata[i];i++;break;
   case 5:
   LSA = 1;LSB = 0;LSC = 1;ab = displaydata[i];i++;break;
   case 6:
   LSA = 0;LSB = 1;LSC = 1;ab = displaydata[i];i++;break;
   case 7:
   LSA = 1;LSB = 1;LSC = 1;ab = displaydata[i];i=0;break;
}
}
void keyscan()
{
static uchar count1=0,count2=0; //計數變量
static bit key_sign=0; //按鍵狀態標志
if(key1==0) //檢測輸入如果為0
{
if((++count1>=100)&&(key_sign==0))
{
key_sign=1; //按鍵自鎖標志置1，防止重復響應
count2++;
if(count2>=3)
count2=0;
switch(count2)
{
case 0: a=0;
b=0;
c=0; break;//清0
case 1: d=1;  break;//計時
case 2: d=0; break;//暫停
}
}
}
else
{
count1=0; //計數變量清0
key_sign=0; //按鍵狀態標志清0
}
}

void TO_time() interrupt 1
{
TL0 = 0x66; //設置定時初值1ms
TH0 = 0xFC; //設置定時初值
if(d)
{
a++;
if(a == 1000)
{
b++;
a=0;
}
if(b == 60)
{
b = 0;
c++;
}
if(c == 60)
c = 0;
}
digdisplay();
}

ID:290305 · 發表于 2019-1-12 11:52

//秒表
#include<reg52.h>
typedef unsigned char u8;
typedef unsigned int u16;
unsigned char DisplayData[4];
unsigned char MMMM=0,MM=0,TTTT=0,TT=0,i=0;
bit A=0;//bit只有0和1兩種值

sbit LSA=P1^0;
sbit LSB=P1^1;
sbit LSC=P1^2;
sbit LSD=P1^3;

u8 code smgduan[10]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90};

void waibuzhongduan()
{
      EA=1;
      EX0=1;
      IT0=1;
      EX1=1;
      IT1=1;
}

void dingshiqizhongduan()
{
      TMOD=0X01;
      TH0=0xD8;
      TL0=0xF0;
      EA=1;
      TR0=0;
      ET0=1;
      PT0=1;//為1時，定時器0中斷為高級優先級，為0時，為低級優先級。

}

void delay10ms(unsigned int c)
{
      unsigned char a,b;
for(c=1;c>0;c--)
      for(b=38;b>0;b--)
         for(a=130;a>0;a--);
}
void Display()
{
      unsigned char i,j;
      for(i=0;i<4;i++)
      {
            switch(i)
            {
                     case (0):LSA=0;LSB=1;LSC=1;LSD=1;break;
                     case (1):LSA=1;LSB=0;LSC=1;LSD=1;break;
                     case (2):LSA=1;LSB=1;LSC=0;LSD=1;break;
                     case (3):LSA=1;LSB=1;LSC=1;LSD=0;break;
            }
            P2=DisplayData[i];
      j=10;
      while(j--);
      P2=0XFF;
      }
}
void XS()
{
      if(A==0)
      {
            DisplayData[0]=smgduan[TT/10];
            DisplayData[1]=smgduan[TT%10]+0x80;
            DisplayData[2]=smgduan[MM/10];
            DisplayData[3]=smgduan[MM%10];
      }
      else
      {
            DisplayData[0]=smgduan[TTTT/10];
            DisplayData[1]=smgduan[TTTT%10]+0x80;
            DisplayData[2]=smgduan[MMMM/10];
            DisplayData[3]=smgduan[MMMM%10];
      }
}

void main()
{
      waibuzhongduan();
      dingshiqizhongduan();
      while(1)
      {
            XS();
            Display();
      }
}
void Int0() interrupt 0
{

            delay10ms(100);
            A=0;
            switch(i)
            {
                     case 0:TR0=1;break;
                     case 1:TR0=0;break;
                     case 2:TT=0,MM=0;break;
            }
            i++;
            if(i>2)
            {
                     i=0;
            }
            delay10ms(10);
            IE0=0;//外部發生中斷時其值為1
}

void Time0() interrupt 1
{

      TH0=0xD8;
      TL0=0xF0;
      MM++;
      if(MM==100)
      {
            MM=0;
            TT++;
                              if (TT==100)
                              {
                                    TT=0;
                              }
      }
      TF0=0;//為1時表示定時器T0計數溢出
}
void Int1() interrupt 2
{

            delay10ms(100);
            TTTT=TT;
            MMMM=MM;
            A=~A;
            delay10ms(10);
            TF1=0;//外部發生中斷時其值為1
}

ID:290305 · 發表于 2019-1-12 11:53

你可以參考下我這個，我的就是按鍵控制啟動和暫停以及清零，你可以稍微改一改

ID:462433 · 發表于 2019-1-12 11:58

時光盜初心發表于 2019-1-12 02:34
可以考慮掉電模式

不可以實現呀！！！用了掉電模式 5秒就斷電就只能重新開始了

ID:123289 · 發表于 2019-1-12 14:35

樓主構思奇妙。
方法很簡單，讀通現有的程序。就知道如果加了。

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單片機秒表程序,怎么在不改動的情況下加個按鍵控制秒表的暫停和計時？