這是一個4行6列矩陣按鍵原代碼
- #include <reg52.h>
- sbit KEY_IN_0 = P1^0;
- sbit KEY_IN_1 = P1^1;
- sbit KEY_IN_2 = P1^2;
- sbit KEY_IN_3 = P1^3;
- sbit KEY_IN_4 = P1^4;
- sbit KEY_IN_5 = P1^5;
- sbit KEY_OUT_1 = P3^0;
- sbit KEY_OUT_2 = P3^1;
- sbit KEY_OUT_3 = P3^2;
- sbit KEY_OUT_4 = P3^6;
- unsigned char code KeyCodeMap[4][6] = { //矩陣按鍵編號到標準鍵盤鍵碼的映射表
- { 0x1B,'1', '2', '3', 0x2A, 0x27 }, //ESC 鍵、數字鍵 1、數字鍵 2、數字鍵 3、向上鍵
- { 0x1A,'4', '5', '6', 0x2B, 0x26 }, //開關屏、數字鍵 4、數字鍵 5、數字鍵 6、向左鍵
- { 0x1C,'7', '8', '9', 0x2D, 0x25 }, //電機開、數字鍵 7、數字鍵 8、數字鍵 9、向下鍵
- { 0x1D,0X06,'0',0x2F, 0x0D, 0x28 } //功能鍵、DEL 鍵、 數字鍵 0、回車鍵、 向右鍵
- };
- unsigned char pdata KeySta[4][6] = { //全部矩陣按鍵的當前狀態
- {1, 1, 1, 1, 1, 1}, {1, 1, 1, 1, 1, 1}, {1, 1, 1, 1, 1, 1}, {1, 1, 1, 1, 1, 1}
- };
- extern void KeyAction(unsigned char keycode);
- /* 按鍵驅動函數，檢測按鍵動作，調度相應動作函數，需在主循環中調用 */
- void KeyDriver()
- {
- unsigned char i, j;
- static unsigned char pdata backup[4][6] = { //按鍵值備份，保存前一次的值
- {1, 1, 1, 1, 1, 1}, {1, 1, 1, 1, 1, 1}, {1, 1, 1, 1, 1, 1}, {1, 1, 1, 1, 1, 1}
- };
- for (i=0; i<4; i++) //循環檢測 4*4 的矩陣按鍵
- {
- for (j=0; j<6; j++)
- {
- if (backup[i][j] != KeySta[i][j]) //檢測按鍵動作
- {
- if (backup[i][j] != 0) //按鍵按下時執行動作
- {
- KeyAction(KeyCodeMap[i][j]); //調用按鍵動作函數
- }
- backup[i][j] = KeySta[i][j]; //刷新前一次的備份值
- }
- }
- }
- }
- /* 按鍵掃描函數，需在定時中斷中調用，推薦調用間隔 1ms */
- void KeyScan()
- {
- unsigned char i;
- static unsigned char keyout = 0; //矩陣按鍵掃描輸出索引
- static unsigned char keybuf[4][6] = { //矩陣按鍵掃描緩沖區
- {0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF}, {0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF},
- {0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF}, {0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF}
- };
- //將一行的 4 個按鍵值移入緩沖區
- keybuf[keyout][0] = (keybuf[keyout][0] << 1) | KEY_IN_0;
- keybuf[keyout][1] = (keybuf[keyout][1] << 1) | KEY_IN_1;
- keybuf[keyout][2] = (keybuf[keyout][2] << 1) | KEY_IN_2;
- keybuf[keyout][3] = (keybuf[keyout][3] << 1) | KEY_IN_3;
- keybuf[keyout][4] = (keybuf[keyout][4] << 1) | KEY_IN_4;
- keybuf[keyout][5] = (keybuf[keyout][5] << 1) | KEY_IN_5;
- //消抖后更新按鍵狀態
- for (i=0; i<6; i++) //每行 4 個按鍵，所以循環 4 次
- {
- if ((keybuf[keyout][i] & 0x0F) == 0x00)
- { //連續 4 次掃描值為 0，即 4*4ms 內都是按下狀態時，可認為按鍵已穩定的按下
- KeySta[keyout][i] = 0;
- }
- else if ((keybuf[keyout][i] & 0x0F) == 0x0F)
- { //連續 4 次掃描值為 1，即 4*4ms 內都是彈起狀態時，可認為按鍵已穩定的彈起
- KeySta[keyout][i] = 1;
- }
- }
- //執行下一次的掃描輸出
- keyout++; //輸出索引遞增
- keyout &= 0x03; //索引值加到 4 即歸零
- switch (keyout) //根據索引，釋放當前輸出引腳，拉低下次的輸出引腳
- {
- case 0: KEY_OUT_4 = 1; KEY_OUT_1 = 0; break;
- case 1: KEY_OUT_1 = 1; KEY_OUT_2 = 0; break;
- case 2: KEY_OUT_2 = 1; KEY_OUT_3 = 0; break;
- case 3: KEY_OUT_3 = 1; KEY_OUT_4 = 0; break;
- default: break;
- }
- }
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