我寫(xiě)了一個(gè)計(jì)算器的程序 但鍵盤(pán)掃描程序?qū)懲炅?燒進(jìn)實(shí)驗(yàn)板 按鍵時(shí)沒(méi)反應(yīng) 計(jì)劃寫(xiě)一個(gè)兩字節(jié)的計(jì)算程序 請(qǐng)高手幫忙看看 感激不盡
#include <stdio.h>
#include <AT89x051.H>
#define liekey (~P0)&0X0F
#define rowkey (~P0)&0XF0
sfr P0 = 0x80;
sfr P2 = 0xA0;
void Initial();
int Data_In();
int Comput();
bit KeyIn(void); //如果有鍵按下返回 1，健值存在 KEYdata
int OP1,OP2,OP,sta;
char KeyData,Buff,Resut;
char DisBuffer[8];
char KeyData=0;
char KeyTab[]={0x7e,0x7d,0x7b,0x0be,0x0bd,0x0bb,0x0de,0x0dd,0x0db,0x0ee,0x77,0x0b7,0x0d7,0x0e7,0x0eb,0x0ed};//鍵盤(pán)的16個(gè)鍵
char Seg_Tab[]={0x3F,0x06,0x5B,0x4F,0x66,0x6D,0x7D,0x07,0x7F,0x6F,0x79};//數(shù)字的0~9 + - */ 對(duì)應(yīng) ASCD "E"對(duì)應(yīng)錯(cuò)誤
void main ()
{ bit flag=0;
Initial();
while (1)
{ flag=KeyIn();
if( flag)
{
DisBuffer[1]=KeyData;
// Display();
}
else
{
}
}
}
bit KeyIn()
{ int i;
char lie,kcode,row; //lie為列對(duì)應(yīng)的低位數(shù)據(jù)的取反 row為行對(duì)應(yīng)的高位數(shù)據(jù)取反
bit keyin=0,last,temp;
lie=liekey;
row=rowkey;
if(lie!=0)
{ //若低位出現(xiàn)非0的情況則為有鍵按下
kcode=~(lie|row); //將按鍵所對(duì)應(yīng)的二進(jìn)制數(shù)據(jù)送給kcode
for(i=0;KeyTab!=kcode&&i<16;i++)
KeyData=i+1;
keyin=1;
}
last=keyin;
keyin=keyin&temp;
temp=~last;
return keyin;
}
void Initial()
{ OP1=0;
OP2=0;
sta=0;
TH0=0xd8; // ;定時(shí)時(shí)間為10ms
TL0=0xf0;
ET0=1;
EA=1;
TR0=1;
DisBuffer[0]=0x3f;
DisBuffer[1]=0x3f;
DisBuffer[2]=0x3f;
DisBuffer[3]=0x3f;
}
void dis (void) interrupt 1 using 2
{
static char dispPost=0;
TR0=0;
EA=0;
TH0=0xd8;
TL0=0xf0;
TF0=0;
P2=0xff; //先熄滅數(shù)碼管 以免產(chǎn)生掃尾現(xiàn)象
P1=dispPost;
P2=DisBuffer[dispPost];
dispPost++;
if (dispPost>=8) dispPost=0;
TR0=1;
EA=1;
} | 
