stm32f103r6源程序+Proteus仿真

ID:329190 · 發表于 2020-5-26 08:40

stm32f103r6的程序帶仿真有4個模塊的

單片機源程序如下:

#include "led.h"
#include "delay.h"
#include "sys.h"
#include "usart.h"
#include "adc.h"
#include "smg.h"
#include "timer.h"
//0,1,2,3,4,5,6,7,8,9,A,B,C,D,E,F, .,全滅
u8 smg_num[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71,0x80,0x00};
u8 smg_wei=0;//數碼管位選
//ADC變量
static u16 adcx=0;
static u16 adcx1=0;
static float temp=0;
u8 num=0;//數碼管值
u8 adc_t=0;//adc采樣時間值
int main(void)
{
LED_Init();
Adc_Init();
while(1) {
adc_t++;
if(adc_t==10)//ADC 采樣
{
adc_t=0;
adcx=Get_Adc_Average(ADC_CH9,3);//ADC原始值
temp=(float)adcx*(3.3/4096);//ADC電壓值
adcx1=temp;
temp-=adcx1;
temp*=1000;
}
Delay(30);
if(adcx>0){
switch(smg_wei)
{
//ADC采樣原始值
case 0: if(adcx>1000)num = smg_num[adcx/1000];
else num = 0x00;
break;
case 1: if(adcx>100) num = smg_num[adcx%1000/100];
else num = 0x00;
break;
case 2: if(adcx>10) num = smg_num[adcx%100/10];
else num = 0x00;
break;
case 3: num = smg_num[adcx%10]; break;
case 4: num = 0x00; break;
//ADC換算后的電壓值
case 5: // num = smg_num[adcx1]|0x01;break;
num = smg_num[adcx1]|0x80;break;
case 6: num = smg_num[(u16)temp/100]; break;
case 7: num = smg_num[(u16)temp%100/10];break;
}
GPIOC->ODR=num;
LED_Wei(smg_wei);
smg_wei++;
if(smg_wei==8)
smg_wei=0;
}
}
}