新手編程遇難題求教

ID:9915 · 發(fā)表于 2014-4-26 16:07

程序如下原本是按key1 數(shù)字加，按key2數(shù)字減，按key3數(shù)字清零，按key4 數(shù)字每秒自動(dòng)加1。�！，F(xiàn)在key1、2、3都正常，按key4沒自動(dòng)加1。求高手賜教。問題出在哪里呢？

#include<reg52.h>
#define uchar unsigned char
#define uint unsigned int
sbit dula=P2^6;
sbit wela=P2^7;
sbit key1=P3^4;
sbit key2=P3^5;
sbit key3=P3^6;
sbit key4=P3^7;
uchar num,numt0;
uchar code table[]={
0x3f,0x06,0x5b,0x4f,
0x66,0x6d,0x7d,0x07,
0x7f,0x6f,0x77,0x7c,
0x39,0x5e,0x79,0x71};

void init() //定時(shí)器0初始化程序
{
TMOD=0x01;
TH0=(65536-45872)/256;
TL0=(65536-45872)%256;
EA=1;
ET0=1;

TR0=1;
}

void delayms(uchar xms) //延時(shí)程序
{
uchar i,j;
for(i=xms;i>0;i--)
for(j=113;j>0;j--);
}

void keyscan() //鍵盤掃描程序
{
if(key1==0) //掃描按鍵1
{
delayms(10);
if(key1==0)
{
num++;
if(num==60)
num=0;
while(!key1);
}
}

if(key2==0) //掃描按鍵2
{
delayms(10);
if(key2==0)
{
if(num==0)
num=60;
num--;
while(!key2);
}
}

if(key3==0) //掃描按鍵3
{
delayms(10);
if(key3==0)
{
num=0;
while(!key3);
}
}

if(key4==0) //掃描按鍵4
{
delayms(10);
if(key4==0)
{
while(!key4);
TR0=!TR0;
}
}
}

void display(uchar laiyuan)//數(shù)碼管顯示掃描程序
{
uchar shi,ge;

shi=laiyuan/10;
ge=laiyuan%10;

dula=1;
P0=table[shi];
dula=0;
P0=0xff;
wela=1;
P0=0xfe;
wela=0;
P0=0x00;
delayms(5);

dula=1;
P0=table[ge];
dula=0;
P0=0xff;
wela=1;
P0=0xfd;
wela=0;
P0=0x00;
delayms(5);
}

void T0_time() interrupt 1 //定時(shí)器0 中斷服務(wù)程序
{
TH0=(65536-45872)/256;
TL0=(65536-45872)%256;
numt0++;
if(numt0==20)
{
numt0=0;
num=num++;
if(num==60)
num=0;
}

}

void main () //主程序
{
num=0x00;
init();
while(1)
{
keyscan();
display(num);
}

}