幫幫忙謝謝了30秒內(nèi)按鈕按5次以上綠燈亮如果在30秒不到5次就紅燈亮，我怎么寫都寫不好

ID:65605 · 發(fā)表于 2014-10-26 18:13

幫我寫一個(gè)30秒內(nèi)按鈕按5次以上綠燈亮如果在30秒不到5次就紅燈亮，我怎么寫都寫不好

ID:44262 · 發(fā)表于 2014-10-26 20:01

程序帖上來看看

ID:65605 · 發(fā)表于 2014-10-26 20:34

#include<reg52.h> #define uint unsigned int unsigned long temp,temp1,temp2; sbit k1=P1^0; sbit LED=P0^0; //LED1燈 void delay(uint z) { uint x,y; for(x=z;x>0;x--) for(y=110;y>0;y--); } void main() { k1=0; LED=0; temp=0; temp1=0; temp2=0; while(1) { if(temp2==1) temp++; if(temp==1000)//達(dá)到時(shí)間從新開始 { temp=0; //時(shí)間清零 temp2=0; temp1=0; } if((k1==0)&&(temp1==0)) //第一次按下判斷 { temp1=1; } else if((k1==1)&&(temp1==1))//第一次放開判斷 { temp1=0; temp2=1;//置起標(biāo)志 } if((k1==0)&&(temp2==1))//第二次按下判斷 { LED=1; temp2=0; temp=0; } } }

ID:65400 · 發(fā)表于 2014-10-26 21:56

建議你建多個(gè)變量a程=，按一下a加1，30

ID:65400 · 發(fā)表于 2014-10-26 22:01

建議你建多個(gè)變量a=0,按一下a加1，30秒到判斷a大于5就綠燈亮，a=0.否則則紅燈亮，a=0

ID:65400 · 發(fā)表于 2014-10-26 22:04

還要最好加個(gè)按鍵消抖

ID:66840 · 發(fā)表于 2014-10-26 22:41

#include<reg52.h>

unsigned int temp,temp1;
sbit k1=P1^0;
sbit LED=P0^0;//lLED1
sbit LED1=P0^1;//lLED2

void delay(unsigned char xms)
{
unsigned char i,j;
for(i=xms; i>0; i--)
{
for(j=110; j>0; j--);
}
}

void main()
{
temp = 0;
temp1 = 0;
while(1)
{
while(k1==0)// 判斷K1是否按下
{
temp++;
delay(1);
temp1++;
if(temp1<30000)//判斷是否在30毫秒內(nèi)
   {
    if(temp >= 5) //判斷次數(shù)是否5次以上
{
LED =0;
LED1 = 1;
temp1 = 0;
temp = 0;
}
else
{
LED =1;
LED1 = 0;
}
    }
}
}
}

ID:66840 · 發(fā)表于 2014-10-26 22:42

希望能夠幫到你

ID:66032 · 發(fā)表于 2014-10-28 11:06

上午剛寫了一個(gè)，運(yùn)行還不錯(cuò)
//用一個(gè)外部中斷做按5次的鍵，一個(gè)定時(shí)器來判斷30秒溢出，如果定時(shí)器在30秒內(nèi)按了5次，外部中斷重新賦初值，這樣防止定時(shí)器在30秒溢出，綠燈亮。反之，定時(shí)器溢出將使得紅燈亮，用12M crystal 和數(shù)碼管+38譯碼器

#include <reg52.h>
#define uchar unsigned char
#define uint unsigned int

code uchar number[] = {0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90};

uchar a[6];

sbit ENLED = P1^4;
sbit ADDR0 = P1^0;
sbit ADDR1 = P1^1;
sbit ADDR2 = P1^2;
sbit ADDR3 = P1^3;
sbit Green_LED =P2^0;
sbit Red_LED =P2^1;

void timer1_init()
{
TMOD |= 0x10;
TMOD &= 0xdf;
TH1 = 0x3C;
TL1 = 0xB0;
TR1 = 1;
}
void interrupter_init()
{
ET1 = 1;
EA=1;       //è«¾ÖÖD¶Ï¿a
EX0=1;       //ía2¿ÖD¶Ï0¿a
IT0=1;       //±ßÑØ′￥·￠
}
void Scanning_Numerical_LED(void)
{
   static uchar j = 0;
      switch(j)
   {
      case 0: ADDR0 = 0;ADDR1 = 0;ADDR2 = 0;j++;P0 = number[a[0]];break;
      case 1: ADDR0 = 1;ADDR1 = 0;ADDR2 = 0;j++;P0 = number[a[1]];break;
      case 2: ADDR0 = 0;ADDR1 = 1;ADDR2 = 0;j++;P0 = number[a[2]];break;
      case 3: ADDR0 = 1;ADDR1 = 1;ADDR2 = 0;j++;P0 = number[a[3]];break;
      case 4: ADDR0 = 0;ADDR1 = 0;ADDR2 = 1;j++;P0 = number[a[4]];break;
      case 5: ADDR0 = 1;ADDR1 = 0;ADDR2 = 1;j = 0;P0 = number[a[5]];break;
      default: break;
}

}

main()
{
ENLED = 0; ADDR3 = 1;
timer1_init();
interrupter_init();
while(1)
{
   Scanning_Numerical_LED();
}

}

void ISR_Key(void) interrupt 0 using 1

{
  uchar counter1;
  counter1++;
  if (counter1==5)
{
   counter1=0;
   TH1 = 0x3C;  //50 ms setting;
   TL1 = 0xB0;
}

}

void interrupt_timer1() interrupt 3
{
   uint sec;
   uchar counter;
   TH1 = 0x3C;  //50 ms setting;
   TL1 = 0xB0;
   counter++;
   if(counter ==20)
   {
      counter = 0;
      sec++;
      if (sec>=30)
         Red_LED=1;
      else Green_LED=1;
      if (sec==1000)
         sec=0;

      a[0] = sec%10;
      a[1] = sec/10%10;
      a[2] = sec/100%10;
      a[3] = sec/1000%10;
      a[4] = sec/10000%10;
      a[5] = sec/100000%10;
   }

}

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幫幫忙謝謝了30秒內(nèi)按鈕按5次以上綠燈亮如果在30秒不到5次就紅燈亮，我怎么寫都寫不好