#include <reg52.h>
#define uint unsigned int
#define uchar unsigned char
#define ulong unsigned long
ulong code table[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f};
ulong l,*s,temp,flag,d,c,sw,wan,qian,bai,shi,ge;
uchar aa,bb,cc,dd,ee,ff,num;
sbit dx=P2^6;
sbit wx=P2^7;
void long_char(ulong l,uchar *s);
void fj();
void inint();
void delay(uint z);
void desplay();
void main()
{
inint();
while(1)
{
if(flag==1)
{
ES=0;
flag=0;
fj();
ES=1;
}
desplay();
}
}
void ckzd(void) interrupt 4
{
if(RI==1)
{
RI=0;
c=SBUF;
num++;
flag=1;
}
if(num==1)
{
aa=SBUF-48;
}
if(num==2)
{
bb=SBUF-48;
}
if(num==3)
{
cc=SBUF-48;
}
if(num==4)
{
dd=SBUF-48;
}
if(num==5)
{
ee=SBUF-48;
}
if(num==6)
{
ff=SBUF-48;
num=0;
}
if(num==6)
{
temp=aa&bb&cc&dd&ee&ff;
}
}
void inint()
{
TMOD=0x20;
SCON=0x50;
TH1= 0xFD;
TL1=TH1;
PCON=0x00;
EA=1;
ES=1;
TR1=1;
wx=0;
dx=0;
}
void fj()
{
sw=temp/100000;
wan=temp%100000/10000;
qian=temp%10000/1000;
bai=temp%1000/100;
shi=temp%100/10;
ge=temp%10;
}
void delay(uint z)
{
uint x,y;
for(x=z;x>0;x--)
for(y=110;y>0;y--);
}
void desplay()
{
wx=1;
P0=0xfe;
wx=0;
P0=0XFF;
dx=1;
P0=table[sw];
dx=0;
delay(3);
wx=1;
P0=0xfd;
wx=0;
P0=0XFF;
dx=1;
P0=table[wan];
dx=0;
delay(3);
wx=1;
P0=0xfb;
wx=0;
P0=0XFF;
dx=1;
P0=table[qian];
dx=0;
delay(3);
wx=1;
P0=0xf7;
wx=0;
P0=0XFF;
dx=1;
P0=table[bai];
dx=0;
delay(3);
wx=1;
P0=0xef;
wx=0;
P0=0XFF;
dx=1;
P0=table[shi];
dx=0;
delay(3);
wx=1;
P0=0xdf;
wx=0;
P0=0XFF;
dx=1;
P0=table[ge];
dx=0;
delay(3);
}
大仙們如何把分6次發送到比如 123456 合并成一個數 temp=123456 |
